5-5x^2-24x=0

Solution for 5-5x^2-24x=0 equation:

5-5x^2-24x=0

a = -5; b = -24; c = +5;
Δ = b2-4ac
Δ = -242-4·(-5)·5
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-26}{2*-5}=\frac{-2}{-10}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+26}{2*-5}=\frac{50}{-10}
=-5
$